Asked by umuro
a projectile's launch speed is five times its speed at maximum height.find the launch angle?
Answers
Answered by
Damon
u = speed * cos theta = speed horizontal which never changes
u/speed = cos theta = 1/5 = o.2
theta = coa^-1 ( 0.2) = 78.5 degrees
u/speed = cos theta = 1/5 = o.2
theta = coa^-1 ( 0.2) = 78.5 degrees
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