Asked by Mackenzie
If an Indian was to drive a 875kg buffalo over the edge of a 33 meter cliff with a horizontal velocity of 8.75 m/s, how far from the base of the cliff would the buffalo land?
Answers
Answered by
bobpursley
time to fall:
hf=hi-4.9t^2 solve for time t.
distance=8.75(t)
hf=hi-4.9t^2 solve for time t.
distance=8.75(t)
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