Asked by samm
joe is building a wooden cylindrical storage box. the box will have a volume og 6pi m^3. for design purposes, the thick wood for the top and the bottom costs $6/m^2 and the thinner wood for the sides cost $5/m^2.
a)express the cost of the wood as a function of the radius. make sure to simplify the expression.
b) if hoe can afford to spend at most $72pi (~ $226.19) to make the storage box, what are the dimensions of the box?
a)express the cost of the wood as a function of the radius. make sure to simplify the expression.
b) if hoe can afford to spend at most $72pi (~ $226.19) to make the storage box, what are the dimensions of the box?
Answers
Answered by
bobpursley
cost=6*2PIr^2+5*2PIr*h
volume=PIr^2*h or h=volume/PIr^2
cost=12PIr^2+20PIr*6PI/PIr^2
volume=PIr^2*h or h=volume/PIr^2
cost=12PIr^2+20PIr*6PI/PIr^2
Answered by
samm
can you please explain how you got these equations?
Answered by
samm
this is what i got:
cost=6*2PIr^2+5*2PIr*h
= 12PIr^2 + 10PIr*h
= 12PIr^2 + 10PIr*(6/r^2)
= 12PIr^2 + (60PI)/r
cost=6*2PIr^2+5*2PIr*h
= 12PIr^2 + 10PIr*h
= 12PIr^2 + 10PIr*(6/r^2)
= 12PIr^2 + (60PI)/r
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.