Asked by Nagwa
what is the local max and local min of
y= 1/21(x-3)(x-3)(x+7)
y= 1/21(x-3)(x-3)(x+7)
Answers
Answered by
Steve
y = 1/21 (x-3)^2 (x+7)
y' = 1/21 (x-3)(3x+11)
That help?
y' = 1/21 (x-3)(3x+11)
That help?
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