Asked by Julian
A photon with a wavelength of 93.8 nm strikes a hydrogen atom, and light is emitted by the atom. How many emission lines would be observed?
Answers
Answered by
DrBob222
hc/wavelength = 2.180E-18(1/1 - 1/x^2)
Substitute for h, c, and wavelength (in meters for wavelength) and solve for x which will be the orbit to which the photon raised the electron in the ground hydrogen atom. Then count the lines it can emit from its excited state. Post your work if you get stuck.
Substitute for h, c, and wavelength (in meters for wavelength) and solve for x which will be the orbit to which the photon raised the electron in the ground hydrogen atom. Then count the lines it can emit from its excited state. Post your work if you get stuck.
Answered by
varsha
686