Asked by Tim
What is the torque produced by a force of 40N j applied at the point 2 m i - 5 m j + 3 m k?
Answers
Answered by
Anonymous
torque=force x arm
= 40j x (2i-5j+3k)=-80k+120i
check that.
= 40j x (2i-5j+3k)=-80k+120i
check that.
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