u = horizontal velocity = 17.4 cos 33
Vi = initial vertical velocity = 17.4 sin 33
v = Vi - 9.8 t
at top v = 0
so at top t = Vi/9.8
it spends the samer asmount of time falling from the top so
time in air = 2 t = 2 Vi/9.8
A Knight of the Round Table fires off a vat of
burning pitch from his catapult at 17.4 m/s,
at 33 ◦
above the horizontal.
The acceleration of gravity is 9.8 m/s
2
.
How long is it in the air?
Answer in units of s.
What is the horizontal component of the velocity?
Answer in units of m/s
1 answer
1 answer