Asked by S
Consider a road over a hill where the top is shaped like a circular bump. This circular arc has its center in the hill below. As a 1200 kg car rounds the top of a hill at a speed of 20.0 m/s, it very breifly loses contact with the pavement. What is the radius of this circular bump?
Answers
Answered by
Damon
mass is irrelevant
when centripetal acceleration = 1 g, the vehicle leaves the road
Va = v^2/r = g
so r = v^2/g = 400/9.81
around 40 meters
when centripetal acceleration = 1 g, the vehicle leaves the road
Va = v^2/r = g
so r = v^2/g = 400/9.81
around 40 meters
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