Asked by Deucalion

Scott is rolling down a 30° slope on his skateboard.The total mass of Scott and the skateboard is 75 kg. The rolling friction between the skateboard wheels and the concrete is 9 N acting backward against the skateboard. The drag force due to air resistance is 11 N acting backward against Scott. What is Scott’s acceleration?
Answered by Damon
weight component down hill = 75*9.81 * sin 30

a = (75*9.81*.5 - 11 -9 )/75
Answered by Anonymous
acceleration equal 4.73
Answered by bob
Scott is stupoood
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