Asked by Ashleigh

From a laboratory process designed to separate water into hydrogen and oxygen gas, a student collected 11.9 g of hydrogen and 78.5 g of oxygen. How much water was originally involved in the process?
Answered by Melissa bowers
10.2g H * 1mol/1g (molar mass) = 10.2mol H
79.5g O * 1mol/16g = about 5 mol O
so about 5 moles of water (H2O so there should be twice as much H as O)
Trust me I'm sure this is right I do after all have an A+ in science so I'm positive I'm right
There are no AI answers yet. The ability to request AI answers is coming soon!