For each value of h, evaluate the following function. Round your answer to four decimal places. lim h->0 (4+h)^(3)-64/h
A) h=0.01
B) h=0.001
C) h=0.0001
D) h=-0.01
E) h=-0.001
F) h=-0.0001
For A I got 48.9
For B I got 48.99
For C I got 48.999
For D I got 47.9
For E I got 47.99
For F I got 47.999
Are these Right any help owuld be greatly appreciated
2 answers
I've seen this one before and queried it before. As h tends to zero, (4+h)^3 approaches 64, but 64/h tends to either plus or minus infinity depending on which side h is approaching zero from, so this isn't what you're calculating. Could you check the function please?
I believe you meant to type
lim h->0 [(4+h)^(3)-64]/h since your calculation answer reflect that calculation.
BTW, my calculator got
A) 48.1201
B) 48.012
C) 48.0012
D) 47.8801
E) 47.9880
F) 47.99988
(I recognized your limit as the derivative of f(x) = x^3 as x approaches 4
eg.
f(x) = x^3
f'(x) = 3x^2
f'(4) = 3(4^2) = 48)
lim h->0 [(4+h)^(3)-64]/h since your calculation answer reflect that calculation.
BTW, my calculator got
A) 48.1201
B) 48.012
C) 48.0012
D) 47.8801
E) 47.9880
F) 47.99988
(I recognized your limit as the derivative of f(x) = x^3 as x approaches 4
eg.
f(x) = x^3
f'(x) = 3x^2
f'(4) = 3(4^2) = 48)