Asked by Anonymous

How do I solve csc^2 x = 5 algebraically over the interval 0 <= x < 2pi?

Answers

Answered by Steve
well, you can rewrite your equation as

sin x = ±1/√5

so, find your reference angle, and use it in each quadrant.
Answered by Anonymous
Is there supposed to be a different method since it says "algebraically"?
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