Asked by Summer
What mass of limestone (in kg) would be required to completely neutralize a 15.2 billion-liter lake that is 1.9×10−5 M in sulfuric acid and 8.6×10−6 M in nitric acid?
Answers
Answered by
bobpursley
For the sulfuric acid..
moles limestone=moles acid
for the nitric acid,
moles limestone=2*moles nitric acid
I will be happy to check your calculations
moles limestone=moles acid
for the nitric acid,
moles limestone=2*moles nitric acid
I will be happy to check your calculations
Answered by
j
5.2*10^5
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