Asked by George
When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas. How many grams of calcium carbonate are needed to produce 81.0 of carbon dioxide at STP?
Is the asnwer 80.95
Is the asnwer 80.95
Answers
Answered by
drwls
The reaction is
CaCO3 -> CaO + CO2
What are the units of your 81.0? Liters? Whatever it is, convert it to moles at STP.
81.0 l is 3.61 moles at STP. You will need the same number of moles of CaCO3.
1 mole of CaCO3 has a mass of 40 + 12 + 48 = 100 g
80.95 g is not the answer.
CaCO3 -> CaO + CO2
What are the units of your 81.0? Liters? Whatever it is, convert it to moles at STP.
81.0 l is 3.61 moles at STP. You will need the same number of moles of CaCO3.
1 mole of CaCO3 has a mass of 40 + 12 + 48 = 100 g
80.95 g is not the answer.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.