Asked by sharon

The complete combustion of ethanol, C2H5OH (FW = 46.0 g/mol), proceeds as follows:
C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l) ΔH = −555 kJ
What is the enthalpy change for combustion of 15.0 g of ethanol
Answered by DrBob222
-555 kJ x (15.0/46.0) = ?
Answered by LOL
-181.0
Answered by Symone
181
Answered by M.P.
-181 kJ
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