Asked by Tarrok
Two vectors A and B have magnitude A = 3.00 and B = 3.00. Their vector product is A x B= -5.00k + 2.00i. What is the angle between A and B?
According to the answer, the angle is 37 degrees. I see where this comes from. However, we know that sin(36,75)=sin(143,25)
So the magnitude of vector C, where vector C is the cross product of vectors A and B is
3*3sin(36,75)=3*3sin(143,25)=5,385
My question is:
Why is 37 degrees the only correct answer if 143 degrees also works?
Thanks for help
According to the answer, the angle is 37 degrees. I see where this comes from. However, we know that sin(36,75)=sin(143,25)
So the magnitude of vector C, where vector C is the cross product of vectors A and B is
3*3sin(36,75)=3*3sin(143,25)=5,385
My question is:
Why is 37 degrees the only correct answer if 143 degrees also works?
Thanks for help
Answers
Answered by
Steve
AxB has to form a right-handed system. If angles greater than 90 degrees are involved, that does not hold.
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