Question

Object 1 (mass=6.4 kg) traveling in the +x direction at a speed of 14.01m/s undergoes an inelastic collision with Object 2 (mass=5.10kg) which is at rest. Object two flies off at a speed of 11.94m/s and an angle θ2=49.8 °. The diagram below is just a sketch and is not meant to have accurate angles. It is possible that Object 1 travels back and to the left, though it is not possible for it to travel in the -y direction. (Do you know why?)
Collision of 2-objects. Object 2 moving into fourth quadrant
a.) What is the total momentum in x direction after the collision?
b.) What is the momentum of Object 1 in the y direction after the collision?
c.)What is the speed of Object 1 after the collision?
d.) What is the angle θ1 in degrees? (Do not enter units)

Answers

bobpursley
You will have to do the law of conservation of momentum in two orthogonal directions, I recommend x and y.

You have two equations then, and you have two unknowns; speed of object 1 in the x, and y directions.

Get busy. A bit of algebra involved.

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