Asked by Melvin V.Rodriguez
The sum of the first "n" terms of series is 2^(n+3) -8.Find the 7th term.
Answers
Answered by
Steve
Assuming a geometric series,
Sn = a(r^n-1)/(r-1)
So, since
2^(n+3)-8 = 2^n*2^3 - 8 = 8*2^n-8 = 8(2^n-1)
Looks like a=8 and r=2.
S7 = 8*2^6 = 512
Sn = a(r^n-1)/(r-1)
So, since
2^(n+3)-8 = 2^n*2^3 - 8 = 8*2^n-8 = 8(2^n-1)
Looks like a=8 and r=2.
S7 = 8*2^6 = 512
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