Asked by Anonymous
A sample of calcium fluoride with a mass of 15.0 g contains 8.40 g of calcium. Assuming that the sample is pure calcium fluoride, how much calcium would be present in a 30.0 g sample?
My answer: 16.8 g Ca
Based on your answer and applying what you know about calcium fluoride, is the 15.0 g sample actually pure calcium fluoride? Explain why or why not. Start with a molecular mass calculation to support your answer.
My molecular mass calculation:
mass of CaF2= (40.08)+(2)(19)= 78.08 g CaF2
I don't know where to go from here.
My answer: 16.8 g Ca
Based on your answer and applying what you know about calcium fluoride, is the 15.0 g sample actually pure calcium fluoride? Explain why or why not. Start with a molecular mass calculation to support your answer.
My molecular mass calculation:
mass of CaF2= (40.08)+(2)(19)= 78.08 g CaF2
I don't know where to go from here.
Answers
Answered by
Damon
CaF2 molar mass = 78.07 check
Ca molar mass = 40.1
F2 molar mass = 2*19 = 38
8.4 g calcium is 8.4/40.1 = .2095 mol
.2095 mol of CaF2 = 16.35 grams, not 15 grams
now part a
30 g * 40.1/78.07 = 15.3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.