It would sure be nice if you showed that you are willing to provide at least a little input on these. Just sayin'
f = x^5 e^(-6x)
f' = x^4 e^(-6x) (5-6x)
so, where is f'=0? Hint: e^(-6x) is never zero.
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
f(x) = x^(5)e^(-6x)
1 answer
1 answer