Asked by Harsha

The third term of an A.P is 8 and 9th term of the A.P.exceeds three times the third term by 2.find the sum of its first 19th terms.
Answered by Steve
a+2d = 8
a+8d = 3(a+2d)+2 = 26

so, 6d = 18, and d=3

Now you can find a, and answer the question.
Answered by rita
a= 2
S19=551
Answered by Anonymous
a+2d=8
a+8d=3(a+2d)+2=26
6d=18
d=6
put d in a+2d= 8
a+2(3)=8
a+6=8
a=8-2
a=2
Sn= n/2[2a+(n-1)d]
=n/2[2(2)+(n-1)3]
n/2[4+3n-3]
2n+3n-3
5n+3
n=5/3
Answered by Anonymous
how in first 26 came, sir pls..can u explain me....
Answered by siri r s
sir pls can u tell me in first how 26 came...?
Answered by Sonu
how 26 came ??
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