Asked by shehzad

mohan changed 2 in to 5 p 20 p and 50 p coins. if the number of 5 p coins was double the number of 20 p coins and the 50 p coins were one fifth the 20 p coins . how many coins of each denomination did he get?
Answered by Steve
If there were x,y,z 5p,20p, and 50p coins, respectively, then

x = 2y
y = 5z
5x+20y+50z = 200

Now just find x,y,z.
Answered by Nishu
Mohan changed 2 into 5p, 20p and 50p coins. If the number of 5p coins was double the number 20p coins, and the 50p coins were one-fifth the 20p coins, how many coins of each denomination di
There are no AI answers yet. The ability to request AI answers is coming soon!