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Anonymous
How do I calculate the following?
tan−1(tan(8)) − tan−1(tan(4))
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Answered by
Steve
Recall that the principal values of arctan are -π/2 < x < π/2
tan^-1(tan(8)) = tan^-1(-6.79) = -1.42
tan^-1(tan(4)) = tan^-1(1.157) = 0.858
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