Question

Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation for this is

S2 (g) + C (s) <---> CS2 (g)

Kc = 9.40 at 900 K

How many grams of CS2 (g) can be prepared by heating 11.7 moles of S2 (g) with excess carbon in a 5.95 L reaction vessel at 900 K until equilibrium is reached?

Answer 1

M S2 = mols/L = ?

.......C + S2 ==> CS2
I.....xs..?M.......0
C..........-x......x
E.........?M-x.....x

Substitute the E line into the Kc expression and solve for x (in mols/L)
Then mols = M x L = ?
Then g CS2 = mols CS2 x molar mass CS2