Acid is required for calcium carbonate to fully dissociate. Determine the volume of 6M hydrochloric acid that must be added to dissolve the mass of CaCO3 you calculated in the question above taking into consideration the equations below.

Question

CaCO3->Ca+CO2
2H+CO2->H2CO3->H2O+CO2
The mass of the question above for CaCO3 was 25.0225

Answer 1

mols CaCO3 = g/molar mass = 25.0225/molar mass = ?

Using the coefficients in the balanced equation, convert mols CaCO3 to mol HCl but the equations you wrote are not correct. I would use
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2 but that isn't the equation you were told to use.
Then M HCl = mols HCl/L HCl. You koow M and mols, solve for L.