Question

A 0.179 g sample of a vitamin C tablet was titrated with 0.1000 M NaOH according to the procedure in this experiment. The titration required 7.08 mL of NaOH solution.

How many moles of NaOH were used in the titration?
How Many moles of Vitamin C were in the sample?
What was the mass percent of vitamin C in the sample?

I got 0.000708 mols of NaOH 0.000708 moles Vitamin C for part A and B.

Answer 1

You have an equation in that lab procedure. Use that equation (balanced).

mols NaOH = M x L = ?
mols vitamin C. Using the coefficients in the balanced equation, convert mols NaOH to mols vitamin C.

Then grams vitamin C = mols vitamin C x molar mass vitamin C = ?

mass% = (grams vitamin C/mass sample)*100 = ?