Asked by Basil
A football is punted into the air and it's height is given by the equation, h(t)=-4.9t^2 + 24.5t + 1
a)how high is it after 1 second?
b)how long does it take to reach it's max height?
c)what is it's max height?
d)how long does it take to hit the ground?
a)how high is it after 1 second?
b)how long does it take to reach it's max height?
c)what is it's max height?
d)how long does it take to hit the ground?
Answers
Answered by
Henry
a. h = -4.9*1^2 + 24.5*1 + 1.
b. Y = Yo + g*Tr = 0 at max h.
Tr = -Yo/g = -24.5/-9.8 = 2.5 s. = Rise
time or time to reach max h.
c. h max = -4.9Tr^2 + 24.5Tr + 1
d. h max = 0.5g*Tf^2
Tf = ?.
T = Tr + Tf.
b. Y = Yo + g*Tr = 0 at max h.
Tr = -Yo/g = -24.5/-9.8 = 2.5 s. = Rise
time or time to reach max h.
c. h max = -4.9Tr^2 + 24.5Tr + 1
d. h max = 0.5g*Tf^2
Tf = ?.
T = Tr + Tf.
Answered by
vum
A football is punted into the air. Its heighth, in meters, aftert seconds is given by the equationh = −4.9t2 + 24.5t + 1.
Answered by
dickface
koochie
Answered by
Henry Hater
I hate henry get out of here henry
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