Asked by SkatingDJ

What is a counterexample of the following conjecture?
Conjecture: Any number that is divisible by 3 is also divisible by 6

36
27
23
18

Is it C, 23? A little confused:p Please help? Thanks
Answered by Steve
no, because 23 is not divisible by 3!

You want B, because 27 is divisible by 3, but <u>not</u> divisible by 6.

Answered by SkatingDJ
Ah, ok, thanks Steve. I got confused to what exactly counterexample meant in this.
There are no AI answers yet. The ability to request AI answers is coming soon!