Asked by Anonymous
A parallelogram has an angle of 50 degs and sides of 5 and 10 inches. What are the lengths of the diagonals? Round each to the nearest tenth of an inch.
Answers
Answered by
Steve
for the short diagonal x,
x^2 = 5^2+10^2-2*5*10 cos50°
for the long diagonal y,
y^2 = 5^2+10^2-2*5*10 cos130°
x^2 = 5^2+10^2-2*5*10 cos50°
for the long diagonal y,
y^2 = 5^2+10^2-2*5*10 cos130°
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.