Asked by Anonymous
* From your hint, I arrived at an answer of 3.46 x 10^4 but the answer key says 3.11 x 10^5 Ib.
A backyard swimming pool holds 185 cubic yards (yd^3) of water. What is the mass of the water in pounds?
DrBob222:
185 yd^3 x (3 ft/yd) x (3 ft/yd) x *3 ft/yd) = ? cubic feet.
Density H2O is 62.3 lbs/ft^3 @ 70 F.
mass = volume x density
mass in lbs = volume in ft^3 x density (lbs/ft^3)
A backyard swimming pool holds 185 cubic yards (yd^3) of water. What is the mass of the water in pounds?
DrBob222:
185 yd^3 x (3 ft/yd) x (3 ft/yd) x *3 ft/yd) = ? cubic feet.
Density H2O is 62.3 lbs/ft^3 @ 70 F.
mass = volume x density
mass in lbs = volume in ft^3 x density (lbs/ft^3)
Answers
Answered by
DrBob222
The problem with your problem is that it doesn't list a temperature so I had to assume a T of 70 F. The density of water changes with T. The density of H2O at 70 F is 62.31.
Here is where I obtained the density of 62.31.
http://www.engineeringtoolbox.com/water-specific-volume-weight-d_661.html
You must have punched the wrong numbers into your calculator.
185 x 27 x 62.3 = 3.11E5.
Here is where I obtained the density of 62.31.
http://www.engineeringtoolbox.com/water-specific-volume-weight-d_661.html
You must have punched the wrong numbers into your calculator.
185 x 27 x 62.3 = 3.11E5.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.