* From your hint, I arrived at an answer of 3.46 x 10^4 but the answer key says 3.11 x 10^5 Ib.

A backyard swimming pool holds 185 cubic yards (yd^3) of water. What is the mass of the water in pounds?

DrBob222:

185 yd^3 x (3 ft/yd) x (3 ft/yd) x *3 ft/yd) = ? cubic feet.

Density H2O is 62.3 lbs/ft^3 @ 70 F.
mass = volume x density
mass in lbs = volume in ft^3 x density (lbs/ft^3)

1 answer

The problem with your problem is that it doesn't list a temperature so I had to assume a T of 70 F. The density of water changes with T. The density of H2O at 70 F is 62.31.
Here is where I obtained the density of 62.31.
http://www.engineeringtoolbox.com/water-specific-volume-weight-d_661.html

You must have punched the wrong numbers into your calculator.
185 x 27 x 62.3 = 3.11E5.
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