y' = (x^2-10x+16)/(x-5)^2
y" = 18/(x-5)^3
So, max/min if y'=0
max if y" < 0, min if y" > 0
The rest is just algebra.
y = x^2 − 9x + 29/x − 5
relative maximum (x, y) =
relative minimum (x, y) =
1 answer
relative maximum (x, y) =
relative minimum (x, y) =
1 answer