Asked by ligas
using the two existing corner sides of an existing wall, what is the maximum rectangular area that can be fenced by a fencing material 30 ft long?
Answers
Answered by
Steve
Assuming the two walls meet at a right angle,
x+y = 30
a = xy = x(30-x)
this is just a parabola, with vertex at x=15. As usual, the area is a square.
You can take the derivative if you want, but no calculus needed here...
x+y = 30
a = xy = x(30-x)
this is just a parabola, with vertex at x=15. As usual, the area is a square.
You can take the derivative if you want, but no calculus needed here...
Answered by
Anonymous
225
Answered by
~' '~
just testing this account after a year
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