Question

If 3.15 mL of vinegar needs 42.5 mL of 0.115 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.40 qt sample of this vinegar?

Answer 1

0.043 liters x 0.100 M = 0.0043 moles of NaOH
0.0043 moles of NaOH = 0.0043 moles of acetic acid
1 quart = 32 fl oz
1 fl oz = 29.57 mL
1.75 quarts x 32 fl oz/qt x 29.57 mL/fl oz = 1656 mL
0.0043 moles / 3.65 mL = 1.178x10^-3 moles/mL
1.178x10^-3 mol/mL x 1.656x10^3 mL = 1.95 mol
1.95 mol x 60.05 g/mol = 117 g
117 g CH3COOH per 1.75 quarts