Asked by Tegan

5.61g of potassium hydroxide(KOH) were dissolved in 200.0 ml of water. The temperature of the water rose from 20.0CE to 27.0CE after dissolving. Calculate the molar heat of dissolving for KOH

mKOH =5.61g
Tf=27C

mH20=200g
Ti=20C
Tf=27C
c=4.18

Q=mct= (200)(4.18)(27-20)
=5852 J
=5.852 kJ

I don't know what to do after this

Answers

Answered by DrBob222
How many mols KOH in 5.61 g KOH? about 0.1 mol? Then you have 5.85 kJ/0.1 mol = ?
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