Question
5.61g of potassium hydroxide(KOH) were dissolved in 200.0 ml of water. The temperature of the water rose from 20.0CE to 27.0CE after dissolving. Calculate the molar heat of dissolving for KOH
mKOH =5.61g
Tf=27C
mH20=200g
Ti=20C
Tf=27C
c=4.18
Q=mct= (200)(4.18)(27-20)
=5852 J
=5.852 kJ
I don't know what to do after this
mKOH =5.61g
Tf=27C
mH20=200g
Ti=20C
Tf=27C
c=4.18
Q=mct= (200)(4.18)(27-20)
=5852 J
=5.852 kJ
I don't know what to do after this
Answers
DrBob222
How many mols KOH in 5.61 g KOH? about 0.1 mol? Then you have 5.85 kJ/0.1 mol = ?