Question
1) How many grams of CH4 (MM = 16.043) are needed to react with 50.0g of CL2 (MM=70.91)?
2) What is the molarity of a solution prepared by dissolving 20.0 g of methanol, CH3OH, oara sufficient water to prepare 500 mL of solution? Show calculations
2) What is the molarity of a solution prepared by dissolving 20.0 g of methanol, CH3OH, oara sufficient water to prepare 500 mL of solution? Show calculations
Answers
1. You need an equation for this since CH4 and Cl2 react to give several products.
2. mols CH3OH = grams/molar mass = ?
Then M = mols CH3OH/L solution
2. mols CH3OH = grams/molar mass = ?
Then M = mols CH3OH/L solution