1) How many grams of CH4 (MM = 16.043) are needed to react with 50.0g of CL2 (MM=70.91)?

2) What is the molarity of a solution prepared by dissolving 20.0 g of methanol, CH3OH, oara sufficient water to prepare 500 mL of solution? Show calculations

1 answer

1. You need an equation for this since CH4 and Cl2 react to give several products.

2. mols CH3OH = grams/molar mass = ?
Then M = mols CH3OH/L solution
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