Question
I have a question about Algebra polynomials. Question goes about this A rectangular painting is twice as long as it is wide. A frame surrounds the painting. The frame is a constant 2 inches wide and has a area of 196 square inches. Find the dimensions of the painting.
I would have liked to make a visual representation of what i wanted but i don't know how to do that so i am just going to write what i inferred from the question
the painting's length is 2*W (w=width) and the width is just w. the frames width is 2 and the area of the frame is 196. How do i go on with the problem. if its just asking for the dimension of the painting wouldn't that mean that i could just multiply the width of the painting and the length of the painting. I know this is wrong because it gives me other numbers. Can anyone explain me how to solve this.
I would have liked to make a visual representation of what i wanted but i don't know how to do that so i am just going to write what i inferred from the question
the painting's length is 2*W (w=width) and the width is just w. the frames width is 2 and the area of the frame is 196. How do i go on with the problem. if its just asking for the dimension of the painting wouldn't that mean that i could just multiply the width of the painting and the length of the painting. I know this is wrong because it gives me other numbers. Can anyone explain me how to solve this.
Answers
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