Question

Write two possible quartic inequalities, one using the less than or equal to symbol (≤) and the other using the greater than or equal to symbol (≥), that correspond to the following solution : -6-√2 <x< -6+√2 or 6-√2 <x< 6+√2

Answer 1

-6-√2 <x< -6+√2
-√2 < x+6 < √2
(x+6)^2 < 2
x^2 + 12x + 36 < 2
x^2 + 12x + 34 < 0