Question

find the perimeter of a triangle whose sides are:

p-24/p^2-3p-18, -3/p+3 and p/p-6

its in fraction form^

Thank You :))

Answer 1

I am about 99% sure you meant:

(p-24)/(p^2 - 3p - 18) , -3/(p+3), and p/(p-6)

just add them up

did you notice that p^2 - 3p -18 = (p+3)(p-6) ??
so you have your common denominator