Asked by Mark
15.00mL sample of a solution of H2SO4 of unknown concentration was titrated with 0.3200 N NaOH. The titration required 21.30mL of the base.
What was the normality of the acid solution?
what was the molarity of the acid solution?
What was the normality of the acid solution?
what was the molarity of the acid solution?
Answers
Answered by
DrBob222
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols NaOH = M x L = ? (Note: the M and N of NaOH are the same.)
Using the coefficients in the balanced equation, convert mols NaOH to mols H2SO4. That will be mols H2SO4 = 1/2 mols NaOH.
Then M H2SO4 = mols H2SO4/L H2SO4 = ?
To convert to N,
N = M*#H titrated. #H in this case is 2 so N = M*2
mols NaOH = M x L = ? (Note: the M and N of NaOH are the same.)
Using the coefficients in the balanced equation, convert mols NaOH to mols H2SO4. That will be mols H2SO4 = 1/2 mols NaOH.
Then M H2SO4 = mols H2SO4/L H2SO4 = ?
To convert to N,
N = M*#H titrated. #H in this case is 2 so N = M*2
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