Question
Let your car have a mass of 825 kg. Your car is moving at a speed of 3.08 m/s when it strikes a parked car and stops in 0.21 s. What force did the parked car exert on it to stop it that quickly?
Answers
Vf = Vo + a*t = 0.
3.08 + a*0.21 = 0.
0.21a = -3.08.
a = -14.7 m/s^2.
F = M*a.
3.08 + a*0.21 = 0.
0.21a = -3.08.
a = -14.7 m/s^2.
F = M*a.
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