Question

A conducting solid sphere (R = 0.24 m, q = 7.6x10^-6 C) is shown in the figure. Using Gauss's Law and two different Gaussian surfaces, determine the electric field (magnitude and direction) at point A, which is 0.000001 m outside the conducting sphere. (Hint: One Gaussian surface is a sphere, and the other is a small right cylinder.)

Magnitude=?
Direction=?

Answer 1

I found that the direction is +x, but am having difficulty with the magnitude.