Question
In a repair shop a truck engine that has mass 429 kg is held in place by four light cables (Figure 1) . Cable A is horizontal, cables B and D are vertical, and cable C makes an angle of 37.1∘ with a vertical wall. Tension in cable A is 729 N .
a.What is the tension in cable B?
b.What is the tension in cable C?
a.What is the tension in cable B?
b.What is the tension in cable C?
Answers
For part B.
T_A = T_C*(sind(37.1))
729N = T_C*(sind(37.1))
T_C = 1250N
T_A = T_C*(sind(37.1))
729N = T_C*(sind(37.1))
T_C = 1250N
For Part A
T_B = mg + costheta*T_C
T_B = 429*9.8 + cos(37.1)*1250
T_B = 5200N
T_B = mg + costheta*T_C
T_B = 429*9.8 + cos(37.1)*1250
T_B = 5200N
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