..........HQ ==> H^+ + Q^-
I......0.035.....0.....0
C........-x......x.....x
E.......0.035-x..x.....x
Convert pKa to Ka, then substitute the E line into Ka expression and solve for x. Post your work if you get stuck.
The weak acid HQ has pKa of 4.89. Calculate the [H3O+] of .035 M HQ.
Thanks.
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