I don,t tink any option there has the anser
because
1/8^2*40
40/8^2
8*5/8^2
(2^3)*5/2^6
2^3-6*5
2^-3*5
5/8........or u can jus inverse it and take to the lowest term
Evaluate the expression 8–^2 x 40
a.16
b.64
c.–64
d.1/64 ****
2 answers
I am guessing you have a typo and you meant:
(8^-2)(40)
then
= (1/64)(40)
= 40/64
= 5/8 , Collins had that also
so I guess that is not what you meant after all.
retype the problem using correct notation.
(8^-2)(40)
then
= (1/64)(40)
= 40/64
= 5/8 , Collins had that also
so I guess that is not what you meant after all.
retype the problem using correct notation.