Asked by Anamika
find the largest number that divides 615 and 963 leaving remainder 6 in each case.
Answers
Answered by
Alankrita
Dear Anamika
To get the largest number (HCF) 1st subtract 6 from 615 and 963
615 - 6 = 609
963 - 6 = 957
Using fundamental theorem
609=3×3×29
957=3×11×29
=》HCF=3×29=87
Therefore, the largest number that divides 615 and 963 leaving remainder 6 in each case is 87.
Hope it is helpful... :-)
To get the largest number (HCF) 1st subtract 6 from 615 and 963
615 - 6 = 609
963 - 6 = 957
Using fundamental theorem
609=3×3×29
957=3×11×29
=》HCF=3×29=87
Therefore, the largest number that divides 615 and 963 leaving remainder 6 in each case is 87.
Hope it is helpful... :-)
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Moupriya Maity
Very very helpful😘😘
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