Asked by mimi
this one is kind of hard
julia can buy 3 jellybeans for 5 cent. she can buy a piece of gum for 2 cent. if julia spends 50 cent in all and gets 28 items, how much of each kind of candy does she have?
julia can buy 3 jellybeans for 5 cent. she can buy a piece of gum for 2 cent. if julia spends 50 cent in all and gets 28 items, how much of each kind of candy does she have?
Answers
Answered by
David Q
Say J = no. of jellybeans
and G = no. of pieces of gum
then J + G = 28 (items)
and 5J/3 + 2G = 50 (cents)
so 5J + 6G = 150
and 5J + 5G = 140
You've now got two equations which differ by exactly 1 x G. Can you finish it off?
and G = no. of pieces of gum
then J + G = 28 (items)
and 5J/3 + 2G = 50 (cents)
so 5J + 6G = 150
and 5J + 5G = 140
You've now got two equations which differ by exactly 1 x G. Can you finish it off?
Answered by
mimi
I d'nt understand this part
so 5J + 6G = 150
and 5J + 5G = 140
so 5J + 6G = 150
and 5J + 5G = 140
Answered by
David Q
They come from multiplying the previous two equations by 5 and 3 respectively. What you're trying to do is get two equations that you can use to eliminate one of the two variables, so after I multiplied the equation that reads 5J/3 + 2G = 50 by 3 to clear the fraction, I then needed to multiply the equation that reads J + G = 28 by 5 to get the same multiplier for J. By good luck, that leaves me with 6G in one equation, and 5G in the other. Is that okay?
Answered by
mimi
Thanks so much
Answered by
David Q
What I *could* have done instead would be to just multiply the first equation by 2 to make the first one have the same number of Gs as the second:
J + G = 28 (items)
5J/3 + 2G = 50 (cents)
Multiplying the first one by 2 would give me:
2J + 2G = 56
5J/3 + 2G = 50
so J/3 = 6
If you solve this for J and then feed that answer back to solve for G, you should get the same answer as before.
J + G = 28 (items)
5J/3 + 2G = 50 (cents)
Multiplying the first one by 2 would give me:
2J + 2G = 56
5J/3 + 2G = 50
so J/3 = 6
If you solve this for J and then feed that answer back to solve for G, you should get the same answer as before.
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