Asked by yifei
Consider two vectors where F1 = 98 N , F2 = 61N,θ1 = 343◦ ,andθ2 = 68◦ ,measuredfrom the positive x axis with the counter-clockwise angular direction as positive.
What is the magnitude of the resultant vec- tor
F⃗ = F⃗ 1 + F⃗ 2
What is the direction of this resultant vec- tor F⃗ ? Use counterclockwise as the positive angulardirection,betweenthelimitsof−180◦ and +180◦ from the positive x axis.
What is the magnitude of the resultant vec- tor
F⃗ = F⃗ 1 + F⃗ 2
What is the direction of this resultant vec- tor F⃗ ? Use counterclockwise as the positive angulardirection,betweenthelimitsof−180◦ and +180◦ from the positive x axis.
Answers
Answered by
yifei
I got a similar question that has been solved, so i understand how to do it now, thanks!
I just need to change the numbers:
F = 61[98o] + 63[50o].
X = 61*Cos98 + 63*Cos50 = -8.49 + 40.50
= 32.0 N.
Y = 61*sin98 + 63*sin50 = 60.41 + 48.26
= 108.7 N.
F = sqrt(X^2+Y^2).
I just need to change the numbers:
F = 61[98o] + 63[50o].
X = 61*Cos98 + 63*Cos50 = -8.49 + 40.50
= 32.0 N.
Y = 61*sin98 + 63*sin50 = 60.41 + 48.26
= 108.7 N.
F = sqrt(X^2+Y^2).
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