Asked by Ronnie
A 2.00 kg box slides down a rough incline plane from a height h of 1.99 m. The box had a speed of 2.77 m/s at the top and a speed of 2.34 m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.)
If I were to calculate the energy lost, it would be from the potential energy, correct?
If I were to calculate the energy lost, it would be from the potential energy, correct?
Answers
Answered by
Damon
energy at top = m g h + (1/2) m v^2
= 2 * 9.81 * 1.99 + .5*2 (2.77)^2
energy at bottom = (1/2) m v^2
= .5*2(2.34)^2
difference is loss to friction. If there were no loss to friction of course it would be going FASTER at the bottom :)
= 2 * 9.81 * 1.99 + .5*2 (2.77)^2
energy at bottom = (1/2) m v^2
= .5*2(2.34)^2
difference is loss to friction. If there were no loss to friction of course it would be going FASTER at the bottom :)
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