Question

P=(64)^-2
Q=1/16^(1/3)
R=8root2

Express pqr as a power of 4

P=4^(-6)
Q=4^(-2/3)
R= ????????

How can i find R?

*please show me the method for future reference*

Thankyou

Answer 1

Using the numbers 3,2 and , which of these problems would have a solution of 4

Answer 2

whats the answer

4 x 2^3/2^3
2 x 2^3/2^4
3 x 2^3/2^4
3 x 2^4/2^4

Answer 3

Erm the first one?

Answer 4

Acutally the second one as 4^3/2^4

Answer 5

no it was actually the first one i turned it in but it said it was the first one but its ok i still got a B

Answer 6

The first one

4x2^3/2^3 =4

Answer 7

Why am i using numbers 3and2. R is 8root2

Answer 8

What is all this nonsense?

Notice all 3 powers can be expressed as a power with base 2, thus as a power with base 4

P = (64)^-2
= (4^3)^-2 = 4^-6

Q = (1/16)^(1/3)
= 16^(-1/3)
= (4^2)^-1/3) = 4^(-2/3)

R = 8√2
= 2^3(2^(1/2))
= 2^(7/2)
= (4^(1/2))^(7/2)
= 4^(7/4)

the PQR = (4^-6)(4^(-2/3))(4^(7/4))
= 4^(-6-2/3+7/4)
= 4^(-59/12)