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Asked by eunice

sofia is 3 years older than Eunice. In 5 years , Sofia will be twice as old as Eunice will then be. Find their present ages.
10 years ago

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Answered by bobpursley
s-3=E
s+5=2(E+5)

solve for s, and e
10 years ago
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sofia is 3 years older than Eunice. In 5 years , Sofia will be twice as old as Eunice will then be. Find their present ages.

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